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SQLite C/C++

发布于 2015-07-25 11:53:28 | 208 次阅读 | 评论: 0 | 来源: 网络整理

安装

在我们开始之前，我们需要在我们的C/ C + +程序中使用SQLite，以确保我们有SQLite库设立在机器上。可以查看SQLite的安装章节，以了解安装过程。

C/C++ 接口API

以下是重要的C＆C++/ SQLite 的接口程序就足够SQLite数据库从C/ C + +程序的使用需求。如果正在寻找一个更复杂的应用程序，那么可以看到 SQLite 的官方文档。

S.N. API & 描述
1 sqlite3_open(const char *filename, sqlite3 **ppDb)

This routine opens a connection to an SQLite database file and returns a database connection object to be used by other SQLite routines.

If the filename argument is NULL or ':memory:', sqlite3_open() will create an in-memory database in RAM that lasts only for the duration of the session.

If filename is not NULL, sqlite3_open() attempts to open the database file by using its value. If no file by that name exists, sqlite3_open() will open a new database file by that name.
2 sqlite3_exec(sqlite3*, const char *sql, sqlite_callback, void *data, char **errmsg)

This routine provides a quick, easy way to execute SQL commands provided by sql argument which can consist of more than one SQL command.

Here, first argument sqlite3 is open database object, sqlite_callback is a call back for whichdata is the 1st argument and errmsg will be return to capture any error raised by the routine.

The sqlite3_exec() routine parses and executes every command given in the sql argument until it reaches the end of the string or encounters an error.
3 sqlite3_close(sqlite3*)

This routine closes a database connection previously opened by a call to sqlite3_open(). All prepared statements associated with the connection should be finalized prior to closing the connection.

If any queries remain that have not been finalized, sqlite3_close() will return SQLITE_BUSY with the error message Unable to close due to unfinalized statements.

连接到数据库

下面的C代码段显示了如何连接到一个现有的数据库。如果数据库不存在，那么它就会被创建，终于将返回一个数据库对象。


#include <stdio.h>
#include <sqlite3.h> 

int main(int argc, char* argv[])
{
   sqlite3 *db;
   char *zErrMsg = 0;
   int rc;

   rc = sqlite3_open("test.db", &db);

   if( rc ){
      fprintf(stderr, "Can't open database: %sn", sqlite3_errmsg(db));
      exit(0);
   }else{
      fprintf(stderr, "Opened database successfullyn");
   }
   sqlite3_close(db);
}

现在，让我们来编译和运行上面的程序在当前目录中创建我们的数据库test.db。按要求可以改变路径。


$gcc test.c -l sqlite3
$./a.out
Opened database successfully

如果要使用C++源代码，可以编译你的代码如下：


$g++ test.c -l sqlite3

在这里，把我们的程序及sqlite3的库，以提供必要的C程序函数。这将创建一个数据库文件test.db 并且在目录结果有如下的内容：


-rwxr-xr-x. 1 root root 7383 May  8 02:06 a.out
-rw-r--r--. 1 root root  323 May  8 02:05 test.c
-rw-r--r--. 1 root root    0 May  8 02:06 test.db

创建表

下面的C代码段将被用于先前创建的数据库中创建一个表：


#include <stdio.h>
#include <stdlib.h>
#include <sqlite3.h> 

static int callback(void *NotUsed, int argc, char **argv, char **azColName){
   int i;
   for(i=0; i<argc; i++){
      printf("%s = %sn", azColName[i], argv[i] ? argv[i] : "NULL");
   }
   printf("n");
   return 0;
}

int main(int argc, char* argv[])
{
   sqlite3 *db;
   char *zErrMsg = 0;
   int  rc;
   char *sql;

   /* Open database */
   rc = sqlite3_open("test.db", &db);
   if( rc ){
      fprintf(stderr, "Can't open database: %sn", sqlite3_errmsg(db));
      exit(0);
   }else{
      fprintf(stdout, "Opened database successfullyn");
   }

   /* Create SQL statement */
   sql = "CREATE TABLE COMPANY("  
         "ID INT PRIMARY KEY     NOT NULL," 
         "NAME           TEXT    NOT NULL," 
         "AGE            INT     NOT NULL," 
         "ADDRESS        CHAR(50)," 
         "SALARY         REAL );";

   /* Execute SQL statement */
   rc = sqlite3_exec(db, sql, callback, 0, &zErrMsg);
   if( rc != SQLITE_OK ){
   fprintf(stderr, "SQL error: %sn", zErrMsg);
      sqlite3_free(zErrMsg);
   }else{
      fprintf(stdout, "Table created successfullyn");
   }
   sqlite3_close(db);
   return 0;
}

上述程序编译和执行时，它会创建 test.db 文件和最终列出 COMPANY 表将如下：


-rwxr-xr-x. 1 root root 9567 May  8 02:31 a.out
-rw-r--r--. 1 root root 1207 May  8 02:31 test.c
-rw-r--r--. 1 root root 3072 May  8 02:31 test.db

INSERT 操作

下面的C代码段显示了我们如何能够创造我们的COMPANY表在上面的例子中创建表中的记录：


#include <stdio.h>
#include <stdlib.h>
#include <sqlite3.h> 

static int callback(void *NotUsed, int argc, char **argv, char **azColName){
   int i;
   for(i=0; i<argc; i++){
      printf("%s = %sn", azColName[i], argv[i] ? argv[i] : "NULL");
   }
   printf("n");
   return 0;
}

int main(int argc, char* argv[])
{
   sqlite3 *db;
   char *zErrMsg = 0;
   int rc;
   char *sql;

   /* Open database */
   rc = sqlite3_open("test.db", &db);
   if( rc ){
      fprintf(stderr, "Can't open database: %sn", sqlite3_errmsg(db));
      exit(0);
   }else{
      fprintf(stderr, "Opened database successfullyn");
   }

   /* Create SQL statement */
   sql = "INSERT INTO COMPANY (ID,NAME,AGE,ADDRESS,SALARY) "  
         "VALUES (1, 'Paul', 32, 'California', 20000.00 ); " 
         "INSERT INTO COMPANY (ID,NAME,AGE,ADDRESS,SALARY) "  
         "VALUES (2, 'Allen', 25, 'Texas', 15000.00 ); "     
         "INSERT INTO COMPANY (ID,NAME,AGE,ADDRESS,SALARY)" 
         "VALUES (3, 'Teddy', 23, 'Norway', 20000.00 );" 
         "INSERT INTO COMPANY (ID,NAME,AGE,ADDRESS,SALARY)" 
         "VALUES (4, 'Mark', 25, 'Rich-Mond ', 65000.00 );";

   /* Execute SQL statement */
   rc = sqlite3_exec(db, sql, callback, 0, &zErrMsg);
   if( rc != SQLITE_OK ){
      fprintf(stderr, "SQL error: %sn", zErrMsg);
      sqlite3_free(zErrMsg);
   }else{
      fprintf(stdout, "Records created successfullyn");
   }
   sqlite3_close(db);
   return 0;
}

上述程序编译和执行时，它会创建COMPANY表中的记录，并会显示以下两行：


Opened database successfully
Records created successfully

SELECT 操作

在我们开始之前获取记录与实际的例子，让我给回调函数，这是我们在我们的例子中使用的一个小细节。这个回调提供了一个SELECT语句的方式获得结果。它具有以下声明：


typedef int (*sqlite3_callback)(
void*,    /* Data provided in the 4th argument of sqlite3_exec() */
int,      /* The number of columns in row */
char**,   /* An array of strings representing fields in the row */
char**    /* An array of strings representing column names */
);

如果上面的回调提供sqlite_exec()程序作为第三个参数，SQLite将调用这个回调函数中处理的每个记录在每个执行SELECT语句在SQL参数。

下面的C代码段，表明我们如何能够获取并显示COMPANY表中在上面的例子中创建表的记录：


#include <stdio.h>
#include <stdlib.h>
#include <sqlite3.h> 

static int callback(void *data, int argc, char **argv, char **azColName){
   int i;
   fprintf(stderr, "%s: ", (const char*)data);
   for(i=0; i<argc; i++){
      printf("%s = %sn", azColName[i], argv[i] ? argv[i] : "NULL");
   }
   printf("n");
   return 0;
}

int main(int argc, char* argv[])
{
   sqlite3 *db;
   char *zErrMsg = 0;
   int rc;
   char *sql;
   const char* data = "Callback function called";

   /* Open database */
   rc = sqlite3_open("test.db", &db);
   if( rc ){
      fprintf(stderr, "Can't open database: %sn", sqlite3_errmsg(db));
      exit(0);
   }else{
      fprintf(stderr, "Opened database successfullyn");
   }

   /* Create SQL statement */
   sql = "SELECT * from COMPANY";

   /* Execute SQL statement */
   rc = sqlite3_exec(db, sql, callback, (void*)data, &zErrMsg);
   if( rc != SQLITE_OK ){
      fprintf(stderr, "SQL error: %sn", zErrMsg);
      sqlite3_free(zErrMsg);
   }else{
      fprintf(stdout, "Operation done successfullyn");
   }
   sqlite3_close(db);
   return 0;
}

上述程序编译和执行时，它会产生以下结果：


Opened database successfully
Callback function called: ID = 1
NAME = Paul
AGE = 32
ADDRESS = California
SALARY = 20000.0

Callback function called: ID = 2
NAME = Allen
AGE = 25
ADDRESS = Texas
SALARY = 15000.0

Callback function called: ID = 3
NAME = Teddy
AGE = 23
ADDRESS = Norway
SALARY = 20000.0

Callback function called: ID = 4
NAME = Mark
AGE = 25
ADDRESS = Rich-Mond
SALARY = 65000.0

Operation done successfully

UPDATE 操作

下面的C代码段显示了我们如何使用UPDATE语句来更新任何记录，然后获取并显示更新的记录，从COMPANY 表：


#include <stdio.h>
#include <stdlib.h>
#include <sqlite3.h> 

static int callback(void *data, int argc, char **argv, char **azColName){
   int i;
   fprintf(stderr, "%s: ", (const char*)data);
   for(i=0; i<argc; i++){
      printf("%s = %sn", azColName[i], argv[i] ? argv[i] : "NULL");
   }
   printf("n");
   return 0;
}

int main(int argc, char* argv[])
{
   sqlite3 *db;
   char *zErrMsg = 0;
   int rc;
   char *sql;
   const char* data = "Callback function called";

   /* Open database */
   rc = sqlite3_open("test.db", &db);
   if( rc ){
      fprintf(stderr, "Can't open database: %sn", sqlite3_errmsg(db));
      exit(0);
   }else{
      fprintf(stderr, "Opened database successfullyn");
   }

   /* Create merged SQL statement */
   sql = "UPDATE COMPANY set SALARY = 25000.00 where ID=1; " 
         "SELECT * from COMPANY";

   /* Execute SQL statement */
   rc = sqlite3_exec(db, sql, callback, (void*)data, &zErrMsg);
   if( rc != SQLITE_OK ){
      fprintf(stderr, "SQL error: %sn", zErrMsg);
      sqlite3_free(zErrMsg);
   }else{
      fprintf(stdout, "Operation done successfullyn");
   }
   sqlite3_close(db);
   return 0;
}

上述程序编译和执行时，它会产生以下结果：


Opened database successfully
Callback function called: ID = 1
NAME = Paul
AGE = 32
ADDRESS = California
SALARY = 25000.0

Callback function called: ID = 2
NAME = Allen
AGE = 25
ADDRESS = Texas
SALARY = 15000.0

Callback function called: ID = 3
NAME = Teddy
AGE = 23
ADDRESS = Norway
SALARY = 20000.0

Callback function called: ID = 4
NAME = Mark
AGE = 25
ADDRESS = Rich-Mond
SALARY = 65000.0

Operation done successfully

删除操作

下面的C代码段显示了我们如何使用DELETE语句删除任何记录，然后获取并显示COMPANY 表剩余的记录：


#include <stdio.h>
#include <stdlib.h>
#include <sqlite3.h> 

static int callback(void *data, int argc, char **argv, char **azColName){
   int i;
   fprintf(stderr, "%s: ", (const char*)data);
   for(i=0; i<argc; i++){
      printf("%s = %sn", azColName[i], argv[i] ? argv[i] : "NULL");
   }
   printf("n");
   return 0;
}

int main(int argc, char* argv[])
{
   sqlite3 *db;
   char *zErrMsg = 0;
   int rc;
   char *sql;
   const char* data = "Callback function called";

   /* Open database */
   rc = sqlite3_open("test.db", &db);
   if( rc ){
      fprintf(stderr, "Can't open database: %sn", sqlite3_errmsg(db));
      exit(0);
   }else{
      fprintf(stderr, "Opened database successfullyn");
   }

   /* Create merged SQL statement */
   sql = "DELETE from COMPANY where ID=2; " 
         "SELECT * from COMPANY";

   /* Execute SQL statement */
   rc = sqlite3_exec(db, sql, callback, (void*)data, &zErrMsg);
   if( rc != SQLITE_OK ){
      fprintf(stderr, "SQL error: %sn", zErrMsg);
      sqlite3_free(zErrMsg);
   }else{
      fprintf(stdout, "Operation done successfullyn");
   }
   sqlite3_close(db);
   return 0;
}

上述程序编译和执行时，它会产生以下结果：


Opened database successfully
Callback function called: ID = 1
NAME = Paul
AGE = 32
ADDRESS = California
SALARY = 20000.0

Callback function called: ID = 3
NAME = Teddy
AGE = 23
ADDRESS = Norway
SALARY = 20000.0

Callback function called: ID = 4
NAME = Mark
AGE = 25
ADDRESS = Rich-Mond
SALARY = 65000.0

Operation done successfully
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